Challenge 4

Solution - 1 ... Rxa3!! 2 bxa3 Qxa1+ 3 Rb1 Re1+ and checkmate soon.
After 1 ... Rxa3!!, if 2 Qxa3 or Rxa3, Black has 2 ... Qe1+ and mate will follow.

Solvers:

  Giorgos Stamatelatos Greece  
  Nadeem abboud Syria  
  Duane Porter USA  
  Dr Aziz A Mhate India  
  Pedro Araiza Mexico  
  Ridit Nimdia India  
  Abby Aneng Malaysia  
  Yazid Bistomie Bin Mat Saad Malaysia  
  Suvendu Parhi India  
  Kay Khine Hlyan Myanmar  
  Steven Hamburgo USA  
  Shant Swarup India  
  Abhinaya Ganesh India  
  Zenaidi Kais Tunisia  
  Usama Ahsan Pakistan  
  Alden Sigua Philippines  
  Abbas CM India  
  Baivab Mishra India  
  Prachi Rungta India  
  Hrishikesh Salvekar India  
  Anil M Prasad India  
  Subinoy Biswas India  
  Nagarajan S India  
  Arjun India  
  Nitin Warde India  

 


Challenge 3

Solution: 1 Rc8+ Rxc8 2 Qa7+ Kxa7 3 bxc8 = N+! and white wins.

Solvers:

  Ahmed Hassan Egypt  
  Luke Scott USA  
  Pedro Araiza Mexico  
  Abby Aneng Malaysia  
  Prakash Shivshankar India  
  Hadi Ghorbani Iran  
  Mika Sjöholm Sweden  
  Praful Zaveri India  
  Radovan Damnjanovic Serbia  
  Douglas T USA  
  Victor Moldova  
  Framcesco Italy  
  Juan José Bayón Palomino Spain  
  Gaurav India  
  Magdy Elmohandes Saudi Arabia  
  Shant Swarup India  
  Charles Wallace USA  
  Anand Vignesh India  
  Hatem Sayed Egypt  
  Athulan India  
  Anupam India  
  Suraj P K India  
  Zenaidi Kais Tunisia  
  Usama Ahsan Pakistan  
  Arjun India  
  Bharat Bhavsar India  
  Harsh Makharia India  
  Omkar Kolekar Canada  
  Shekhar Verma India  
  R Raman India  

 


Challenge 2

Solution: 1 Qxf4! Bxf4 2 Rxh5 gxh5 3 Rxh5 and black can't avoid mate.

Solvers:

  Luke Scott USA  
  Miguel Zialcita Philippines  
  Lars Nonnenberg Germany  
  Sayantan Das India  
  Demetrius Goins USA  
  Santanu Bandyopadhyay USA  
  Gautam Sabhahit UAE  
  Aditya Yajaman India  
  Shant Swarup India  
  Robinsoniv Liporov Philippines  
  Erfan Iran  
  Karthikeyan India  
  J Pankrac Canada  
  Harsh Makharia India  
  Dan Bujor Romania  
       


Challenge 1

Solution - 1 Bxd5+ cxd5 2 Qxf8+ Kxf8 3 Rc8+ and mate on the next move.

Solvers:

  Lohanathan Malaysia  
  A.G.Vinothraj Srilanka  
  Ashwani India  
  Jimmy Lim Indonesia  
  Anand Kashelkar India  
  Hassan Sudan  
  William Wu ChengYuan Singapore  
  Rahul Joshi India  
  Luis Catibayan Philippines  
  Kaustubh Sakhalkar India  
  Federico Loayza Sanjines Bolivia  
  Kinjal Makharia India  
  Shivam Agrawal India  

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